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sqrt(4x-1)=y la ecuación

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Solución numérica:

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Solución

Ha introducido [src] 
  _________    
\/ 4*x - 1  = y
4x−1=y\sqrt{4 x - 1} = y
Simplificar
Gráfica
Respuesta rápida [src] 
           2        2                   
     1   im (y)   re (y)   I*im(y)*re(y)
x1 = - - ------ + ------ + -------------
     4     4        4            2
x1=(re⁡(y))24+ire⁡(y)im⁡(y)2−(im⁡(y))24+14x_{1} = \frac{\left(\operatorname{re}{\left(y\right)}\right)^{2}}{4} + \frac{i \operatorname{re}{\left(y\right)} \operatorname{im}{\left(y\right)}}{2} - \frac{\left(\operatorname{im}{\left(y\right)}\right)^{2}}{4} + \frac{1}{4} 
x1 = re(y)^2/4 + i*re(y)*im(y)/2 - im(y)^2/4 + 1/4
Suma y producto de raíces [src] 
suma
      2        2                   
1   im (y)   re (y)   I*im(y)*re(y)
- - ------ + ------ + -------------
4     4        4            2
(re⁡(y))24+ire⁡(y)im⁡(y)2−(im⁡(y))24+14\frac{\left(\operatorname{re}{\left(y\right)}\right)^{2}}{4} + \frac{i \operatorname{re}{\left(y\right)} \operatorname{im}{\left(y\right)}}{2} - \frac{\left(\operatorname{im}{\left(y\right)}\right)^{2}}{4} + \frac{1}{4} 
=
      2        2                   
1   im (y)   re (y)   I*im(y)*re(y)
- - ------ + ------ + -------------
4     4        4            2
(re⁡(y))24+ire⁡(y)im⁡(y)2−(im⁡(y))24+14\frac{\left(\operatorname{re}{\left(y\right)}\right)^{2}}{4} + \frac{i \operatorname{re}{\left(y\right)} \operatorname{im}{\left(y\right)}}{2} - \frac{\left(\operatorname{im}{\left(y\right)}\right)^{2}}{4} + \frac{1}{4} 
producto
      2        2                   
1   im (y)   re (y)   I*im(y)*re(y)
- - ------ + ------ + -------------
4     4        4            2
(re⁡(y))24+ire⁡(y)im⁡(y)2−(im⁡(y))24+14\frac{\left(\operatorname{re}{\left(y\right)}\right)^{2}}{4} + \frac{i \operatorname{re}{\left(y\right)} \operatorname{im}{\left(y\right)}}{2} - \frac{\left(\operatorname{im}{\left(y\right)}\right)^{2}}{4} + \frac{1}{4} 
=
      2        2                   
1   im (y)   re (y)   I*im(y)*re(y)
- - ------ + ------ + -------------
4     4        4            2
(re⁡(y))24+ire⁡(y)im⁡(y)2−(im⁡(y))24+14\frac{\left(\operatorname{re}{\left(y\right)}\right)^{2}}{4} + \frac{i \operatorname{re}{\left(y\right)} \operatorname{im}{\left(y\right)}}{2} - \frac{\left(\operatorname{im}{\left(y\right)}\right)^{2}}{4} + \frac{1}{4} 
1/4 - im(y)^2/4 + re(y)^2/4 + i*im(y)*re(y)/2
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