yy^i=(1-2x)/y la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
/ -I \ / -I \
| ---| | ---|
| 2/5 5 | | 2/5 5 |
y1 = I*im\(1 - 2*x) *(1 - 2*x) / + re\(1 - 2*x) *(1 - 2*x) /
$$y_{1} = \operatorname{re}{\left(\left(1 - 2 x\right)^{\frac{2}{5}} \left(1 - 2 x\right)^{- \frac{i}{5}}\right)} + i \operatorname{im}{\left(\left(1 - 2 x\right)^{\frac{2}{5}} \left(1 - 2 x\right)^{- \frac{i}{5}}\right)}$$
y1 = re((1 - 2*x)^(2/5)*(1 - 2*x)^(-i/5)) + i*im((1 - 2*x)^(2/5)*(1 - 2*x)^(-i/5))
Suma y producto de raíces
[src]
/ -I \ / -I \
| ---| | ---|
| 2/5 5 | | 2/5 5 |
I*im\(1 - 2*x) *(1 - 2*x) / + re\(1 - 2*x) *(1 - 2*x) /
$$\operatorname{re}{\left(\left(1 - 2 x\right)^{\frac{2}{5}} \left(1 - 2 x\right)^{- \frac{i}{5}}\right)} + i \operatorname{im}{\left(\left(1 - 2 x\right)^{\frac{2}{5}} \left(1 - 2 x\right)^{- \frac{i}{5}}\right)}$$
/ -I \ / -I \
| ---| | ---|
| 2/5 5 | | 2/5 5 |
I*im\(1 - 2*x) *(1 - 2*x) / + re\(1 - 2*x) *(1 - 2*x) /
$$\operatorname{re}{\left(\left(1 - 2 x\right)^{\frac{2}{5}} \left(1 - 2 x\right)^{- \frac{i}{5}}\right)} + i \operatorname{im}{\left(\left(1 - 2 x\right)^{\frac{2}{5}} \left(1 - 2 x\right)^{- \frac{i}{5}}\right)}$$
/ -I \ / -I \
| ---| | ---|
| 2/5 5 | | 2/5 5 |
I*im\(1 - 2*x) *(1 - 2*x) / + re\(1 - 2*x) *(1 - 2*x) /
$$\operatorname{re}{\left(\left(1 - 2 x\right)^{\frac{2}{5}} \left(1 - 2 x\right)^{- \frac{i}{5}}\right)} + i \operatorname{im}{\left(\left(1 - 2 x\right)^{\frac{2}{5}} \left(1 - 2 x\right)^{- \frac{i}{5}}\right)}$$
/ -I \ / -I \
| ---| | ---|
| 2/5 5 | | 2/5 5 |
I*im\(1 - 2*x) *(1 - 2*x) / + re\(1 - 2*x) *(1 - 2*x) /
$$\operatorname{re}{\left(\left(1 - 2 x\right)^{\frac{2}{5}} \left(1 - 2 x\right)^{- \frac{i}{5}}\right)} + i \operatorname{im}{\left(\left(1 - 2 x\right)^{\frac{2}{5}} \left(1 - 2 x\right)^{- \frac{i}{5}}\right)}$$
i*im((1 - 2*x)^(2/5)*(1 - 2*x)^(-i/5)) + re((1 - 2*x)^(2/5)*(1 - 2*x)^(-i/5))