|4*x - 1| >= |2*x + 3|
(-oo, -1/3] U [2, oo)
x in Union(Interval(-oo, -1/3), Interval(2, oo))
Or(And(2 <= x, x < oo), And(x <= -1/3, -oo < x))
((2 <= x)∧(x < oo))∨((x <= -1/3)∧(-oo < x))