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log2(x+2)≥log0,5(x)+log23. desigualdades

En la desigualdad la incógnita

Solución

Ha introducido [src]
log(x + 2)                          
---------- >= log(0.0)*5*x + log(23)
  log(2)                            
$$\frac{\log{\left(x + 2 \right)}}{\log{\left(2 \right)}} \geq x 5 \log{\left(0.0 \right)} + \log{\left(23 \right)}$$
log(x + 2)/log(2) >= x*(5*log(0.0)) + log(23)