Sr Examen

log2(x+1)>logx+1(16) desigualdades

En la desigualdad la incógnita

Solución

Ha introducido [src]
log(x + 1)              
---------- > log(x) + 16
  log(2)                
$$\frac{\log{\left(x + 1 \right)}}{\log{\left(2 \right)}} > \log{\left(x \right)} + 16$$
log(x + 1)/log(2) > log(x) + 16