|2*x - 1| > |x - 1|
Or(And(-oo < x, x < 0), And(2/3 < x, x < oo))
((-oo < x)∧(x < 0))∨((2/3 < x)∧(x < oo))
(-oo, 0) U (2/3, oo)
x in Union(Interval.open(-oo, 0), Interval.open(2/3, oo))