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loga(7-x)≥2loga(x-5) desigualdades

En la desigualdad la incógnita

Solución

Ha introducido [src]
log(7 - x)      log(x - 5)
---------- >= 2*----------
  log(a)          log(a)  
log(7x)log(a)2log(x5)log(a)\frac{\log{\left(7 - x \right)}}{\log{\left(a \right)}} \geq 2 \frac{\log{\left(x - 5 \right)}}{\log{\left(a \right)}}
log(7 - x)/log(a) >= 2*(log(x - 5)/log(a))