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(((x^2)-x)log8((x^2)+4x-4))/(x-2)≥((log8(-x^2)-4x+4)^6)/(x-2) desigualdades

En la desigualdad la incógnita

Solución

Ha introducido [src]
                                                  6
            / 2          \    /   /  2\          \ 
/ 2    \ log\x  + 4*x - 4/    |log\-x /          | 
\x  - x/*-----------------    |-------- - 4*x + 4| 
               log(8)         \ log(8)           / 
-------------------------- >= ---------------------
          x - 2                       x - 2        
$$\frac{\frac{\log{\left(\left(x^{2} + 4 x\right) - 4 \right)}}{\log{\left(8 \right)}} \left(x^{2} - x\right)}{x - 2} \geq \frac{\left(\left(- 4 x + \frac{\log{\left(- x^{2} \right)}}{\log{\left(8 \right)}}\right) + 4\right)^{6}}{x - 2}$$
((log(x^2 + 4*x - 4)/log(8))*(x^2 - x))/(x - 2) >= (-4*x + log(-x^2)/log(8) + 4)^6/(x - 2)