___ \/ 3 - x > x - 2
-x + sqrt(3) > x - 2
___ \/ 3 (-oo, 1 + -----) 2
x in Interval.open(-oo, sqrt(3)/2 + 1)
/ ___\ | \/ 3 | And|-oo < x, x < 1 + -----| \ 2 /
(-oo < x)∧(x < 1 + sqrt(3)/2)