Integral de (3x+1)/(5-x^2-2x) dx
Solución
Respuesta (Indefinida)
[src]
// / ___ \ \
|| ___ |\/ 6 *(1 + x)| |
||-\/ 6 *acoth|-------------| |
/ || \ 6 / 2 |
| ||---------------------------- for (1 + x) > 6| / 2 \
| 3*x + 1 || 6 | 3*log\-5 + x + 2*x/
| ------------ dx = C + 2*|< | - --------------------
| 2 || / ___ \ | 2
| 5 - x - 2*x || ___ |\/ 6 *(1 + x)| |
| ||-\/ 6 *atanh|-------------| |
/ || \ 6 / 2 |
||---------------------------- for (1 + x) < 6|
\\ 6 /
∫−2x+(5−x2)3x+1dx=C+2⎩⎨⎧−66acoth(66(x+1))−66atanh(66(x+1))for(x+1)2>6for(x+1)2<6−23log(x2+2x−5)
Gráfica
/ ___\ / ___\ / ___\ / ___\
|3 \/ 6 | / / ___\\ |3 \/ 6 | / ___\ |3 \/ 6 | / / ___\\ |3 \/ 6 | / ___\
|- - -----|*\pi*I + log\-1 + \/ 6 // + |- + -----|*log\1 + \/ 6 / - |- - -----|*\pi*I + log\-2 + \/ 6 // - |- + -----|*log\2 + \/ 6 /
\2 6 / \2 6 / \2 6 / \2 6 /
−(66+23)log(2+6)+(66+23)log(1+6)−(23−66)(log(−2+6)+iπ)+(23−66)(log(−1+6)+iπ)
=
/ ___\ / ___\ / ___\ / ___\
|3 \/ 6 | / / ___\\ |3 \/ 6 | / ___\ |3 \/ 6 | / / ___\\ |3 \/ 6 | / ___\
|- - -----|*\pi*I + log\-1 + \/ 6 // + |- + -----|*log\1 + \/ 6 / - |- - -----|*\pi*I + log\-2 + \/ 6 // - |- + -----|*log\2 + \/ 6 /
\2 6 / \2 6 / \2 6 / \2 6 /
−(66+23)log(2+6)+(66+23)log(1+6)−(23−66)(log(−2+6)+iπ)+(23−66)(log(−1+6)+iπ)
(3/2 - sqrt(6)/6)*(pi*i + log(-1 + sqrt(6))) + (3/2 + sqrt(6)/6)*log(1 + sqrt(6)) - (3/2 - sqrt(6)/6)*(pi*i + log(-2 + sqrt(6))) - (3/2 + sqrt(6)/6)*log(2 + sqrt(6))
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.