Integral de (3*2^x-4*5^x+e*2^x+1)/2^x dx
Solución
Solución detallada
Vuelva a escribir el integrando:
( 2 x e + ( 3 ⋅ 2 x − 4 ⋅ 5 x ) ) + 1 2 x = e + 3 − 4 ⋅ 2 − x 5 x + 2 − x \frac{\left(2^{x} e + \left(3 \cdot 2^{x} - 4 \cdot 5^{x}\right)\right) + 1}{2^{x}} = e + 3 - 4 \cdot 2^{- x} 5^{x} + 2^{- x} 2 x ( 2 x e + ( 3 ⋅ 2 x − 4 ⋅ 5 x ) ) + 1 = e + 3 − 4 ⋅ 2 − x 5 x + 2 − x
Integramos término a término:
La integral de las constantes tienen esta constante multiplicada por la variable de integración:
∫ e d x = e x \int e\, dx = e x ∫ e d x = e x
La integral de las constantes tienen esta constante multiplicada por la variable de integración:
∫ 3 d x = 3 x \int 3\, dx = 3 x ∫ 3 d x = 3 x
La integral del producto de una función por una constante es la constante por la integral de esta función:
∫ ( − 4 ⋅ 2 − x 5 x ) d x = − 4 ∫ 2 − x 5 x d x \int \left(- 4 \cdot 2^{- x} 5^{x}\right)\, dx = - 4 \int 2^{- x} 5^{x}\, dx ∫ ( − 4 ⋅ 2 − x 5 x ) d x = − 4 ∫ 2 − x 5 x d x
No puedo encontrar los pasos en la búsqueda de esta integral.
Pero la integral
− 5 x − 2 x log ( 5 ) + 2 x log ( 2 ) - \frac{5^{x}}{- 2^{x} \log{\left(5 \right)} + 2^{x} \log{\left(2 \right)}} − − 2 x l o g ( 5 ) + 2 x l o g ( 2 ) 5 x
Por lo tanto, el resultado es: 4 ⋅ 5 x − 2 x log ( 5 ) + 2 x log ( 2 ) \frac{4 \cdot 5^{x}}{- 2^{x} \log{\left(5 \right)} + 2^{x} \log{\left(2 \right)}} − 2 x l o g ( 5 ) + 2 x l o g ( 2 ) 4 ⋅ 5 x
que u = − x u = - x u = − x .
Luego que d u = − d x du = - dx d u = − d x y ponemos − d u - du − d u :
∫ ( − 2 u ) d u \int \left(- 2^{u}\right)\, du ∫ ( − 2 u ) d u
La integral del producto de una función por una constante es la constante por la integral de esta función:
∫ 2 u d u = − ∫ 2 u d u \int 2^{u}\, du = - \int 2^{u}\, du ∫ 2 u d u = − ∫ 2 u d u
La integral de la función exponencial es igual a la mesma, dividida por la base de logaritmo natural.
∫ 2 u d u = 2 u log ( 2 ) \int 2^{u}\, du = \frac{2^{u}}{\log{\left(2 \right)}} ∫ 2 u d u = l o g ( 2 ) 2 u
Por lo tanto, el resultado es: − 2 u log ( 2 ) - \frac{2^{u}}{\log{\left(2 \right)}} − l o g ( 2 ) 2 u
Si ahora sustituir u u u más en:
− 2 − x log ( 2 ) - \frac{2^{- x}}{\log{\left(2 \right)}} − l o g ( 2 ) 2 − x
El resultado es: 4 ⋅ 5 x − 2 x log ( 5 ) + 2 x log ( 2 ) + e x + 3 x − 2 − x log ( 2 ) \frac{4 \cdot 5^{x}}{- 2^{x} \log{\left(5 \right)} + 2^{x} \log{\left(2 \right)}} + e x + 3 x - \frac{2^{- x}}{\log{\left(2 \right)}} − 2 x l o g ( 5 ) + 2 x l o g ( 2 ) 4 ⋅ 5 x + e x + 3 x − l o g ( 2 ) 2 − x
Ahora simplificar:
4 − x ( 1 0 x log ( 16 ) + 2 x log ( 5 2 ) + 4 x x log ( 2 log ( ( 2 5 ) e + 3 ) ) ) log ( 2 5 ) log ( 2 ) \frac{4^{- x} \left(10^{x} \log{\left(16 \right)} + 2^{x} \log{\left(\frac{5}{2} \right)} + 4^{x} x \log{\left(2^{\log{\left(\left(\frac{2}{5}\right)^{e + 3} \right)}} \right)}\right)}{\log{\left(\frac{2}{5} \right)} \log{\left(2 \right)}} l o g ( 5 2 ) l o g ( 2 ) 4 − x ( 1 0 x l o g ( 16 ) + 2 x l o g ( 2 5 ) + 4 x x l o g ( 2 l o g ( ( 5 2 ) e + 3 ) ) )
Añadimos la constante de integración:
4 − x ( 1 0 x log ( 16 ) + 2 x log ( 5 2 ) + 4 x x log ( 2 log ( ( 2 5 ) e + 3 ) ) ) log ( 2 5 ) log ( 2 ) + c o n s t a n t \frac{4^{- x} \left(10^{x} \log{\left(16 \right)} + 2^{x} \log{\left(\frac{5}{2} \right)} + 4^{x} x \log{\left(2^{\log{\left(\left(\frac{2}{5}\right)^{e + 3} \right)}} \right)}\right)}{\log{\left(\frac{2}{5} \right)} \log{\left(2 \right)}}+ \mathrm{constant} l o g ( 5 2 ) l o g ( 2 ) 4 − x ( 1 0 x l o g ( 16 ) + 2 x l o g ( 2 5 ) + 4 x x l o g ( 2 l o g ( ( 5 2 ) e + 3 ) ) ) + constant
Respuesta:
4 − x ( 1 0 x log ( 16 ) + 2 x log ( 5 2 ) + 4 x x log ( 2 log ( ( 2 5 ) e + 3 ) ) ) log ( 2 5 ) log ( 2 ) + c o n s t a n t \frac{4^{- x} \left(10^{x} \log{\left(16 \right)} + 2^{x} \log{\left(\frac{5}{2} \right)} + 4^{x} x \log{\left(2^{\log{\left(\left(\frac{2}{5}\right)^{e + 3} \right)}} \right)}\right)}{\log{\left(\frac{2}{5} \right)} \log{\left(2 \right)}}+ \mathrm{constant} l o g ( 5 2 ) l o g ( 2 ) 4 − x ( 1 0 x l o g ( 16 ) + 2 x l o g ( 2 5 ) + 4 x x l o g ( 2 l o g ( ( 5 2 ) e + 3 ) ) ) + constant
Respuesta (Indefinida)
[src]
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| x x x -x x
| 3*2 - 4*5 + E*2 + 1 2 4*5
| ---------------------- dx = C + 3*x + E*x - ------ + ---------------------
| x log(2) x x
| 2 2 *log(2) - 2 *log(5)
|
/
∫ ( 2 x e + ( 3 ⋅ 2 x − 4 ⋅ 5 x ) ) + 1 2 x d x = 4 ⋅ 5 x − 2 x log ( 5 ) + 2 x log ( 2 ) + C + e x + 3 x − 2 − x log ( 2 ) \int \frac{\left(2^{x} e + \left(3 \cdot 2^{x} - 4 \cdot 5^{x}\right)\right) + 1}{2^{x}}\, dx = \frac{4 \cdot 5^{x}}{- 2^{x} \log{\left(5 \right)} + 2^{x} \log{\left(2 \right)}} + C + e x + 3 x - \frac{2^{- x}}{\log{\left(2 \right)}} ∫ 2 x ( 2 x e + ( 3 ⋅ 2 x − 4 ⋅ 5 x ) ) + 1 d x = − 2 x log ( 5 ) + 2 x log ( 2 ) 4 ⋅ 5 x + C + e x + 3 x − log ( 2 ) 2 − x
Gráfica
0.00 1.00 0.10 0.20 0.30 0.40 0.50 0.60 0.70 0.80 0.90 -10 10
2 2
log(5) 3*log(2) 2*log(5) 12*log (2) 38*log(2) 12*log(2)*log(5) 4*E*log (2) 4*E*log(2)*log(5)
- ----------------------- - ----------------------- + --------------------------- + --------------------------- + --------------------------- - --------------------------- + --------------------------- - ---------------------------
2 2 2 2 2 2 2 2
log (2) - log(2)*log(5) log (2) - log(2)*log(5) 4*log (2) - 4*log(2)*log(5) 4*log (2) - 4*log(2)*log(5) 4*log (2) - 4*log(2)*log(5) 4*log (2) - 4*log(2)*log(5) 4*log (2) - 4*log(2)*log(5) 4*log (2) - 4*log(2)*log(5)
38 log ( 2 ) − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 + 12 log ( 2 ) 2 − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 + 4 e log ( 2 ) 2 − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 + 2 log ( 5 ) − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 − log ( 5 ) − log ( 2 ) log ( 5 ) + log ( 2 ) 2 − 3 log ( 2 ) − log ( 2 ) log ( 5 ) + log ( 2 ) 2 − 4 e log ( 2 ) log ( 5 ) − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 − 12 log ( 2 ) log ( 5 ) − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 \frac{38 \log{\left(2 \right)}}{- 4 \log{\left(2 \right)} \log{\left(5 \right)} + 4 \log{\left(2 \right)}^{2}} + \frac{12 \log{\left(2 \right)}^{2}}{- 4 \log{\left(2 \right)} \log{\left(5 \right)} + 4 \log{\left(2 \right)}^{2}} + \frac{4 e \log{\left(2 \right)}^{2}}{- 4 \log{\left(2 \right)} \log{\left(5 \right)} + 4 \log{\left(2 \right)}^{2}} + \frac{2 \log{\left(5 \right)}}{- 4 \log{\left(2 \right)} \log{\left(5 \right)} + 4 \log{\left(2 \right)}^{2}} - \frac{\log{\left(5 \right)}}{- \log{\left(2 \right)} \log{\left(5 \right)} + \log{\left(2 \right)}^{2}} - \frac{3 \log{\left(2 \right)}}{- \log{\left(2 \right)} \log{\left(5 \right)} + \log{\left(2 \right)}^{2}} - \frac{4 e \log{\left(2 \right)} \log{\left(5 \right)}}{- 4 \log{\left(2 \right)} \log{\left(5 \right)} + 4 \log{\left(2 \right)}^{2}} - \frac{12 \log{\left(2 \right)} \log{\left(5 \right)}}{- 4 \log{\left(2 \right)} \log{\left(5 \right)} + 4 \log{\left(2 \right)}^{2}} − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 38 log ( 2 ) + − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 12 log ( 2 ) 2 + − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 4 e log ( 2 ) 2 + − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 2 log ( 5 ) − − log ( 2 ) log ( 5 ) + log ( 2 ) 2 log ( 5 ) − − log ( 2 ) log ( 5 ) + log ( 2 ) 2 3 log ( 2 ) − − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 4 e log ( 2 ) log ( 5 ) − − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 12 log ( 2 ) log ( 5 )
=
2 2
log(5) 3*log(2) 2*log(5) 12*log (2) 38*log(2) 12*log(2)*log(5) 4*E*log (2) 4*E*log(2)*log(5)
- ----------------------- - ----------------------- + --------------------------- + --------------------------- + --------------------------- - --------------------------- + --------------------------- - ---------------------------
2 2 2 2 2 2 2 2
log (2) - log(2)*log(5) log (2) - log(2)*log(5) 4*log (2) - 4*log(2)*log(5) 4*log (2) - 4*log(2)*log(5) 4*log (2) - 4*log(2)*log(5) 4*log (2) - 4*log(2)*log(5) 4*log (2) - 4*log(2)*log(5) 4*log (2) - 4*log(2)*log(5)
38 log ( 2 ) − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 + 12 log ( 2 ) 2 − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 + 4 e log ( 2 ) 2 − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 + 2 log ( 5 ) − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 − log ( 5 ) − log ( 2 ) log ( 5 ) + log ( 2 ) 2 − 3 log ( 2 ) − log ( 2 ) log ( 5 ) + log ( 2 ) 2 − 4 e log ( 2 ) log ( 5 ) − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 − 12 log ( 2 ) log ( 5 ) − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 \frac{38 \log{\left(2 \right)}}{- 4 \log{\left(2 \right)} \log{\left(5 \right)} + 4 \log{\left(2 \right)}^{2}} + \frac{12 \log{\left(2 \right)}^{2}}{- 4 \log{\left(2 \right)} \log{\left(5 \right)} + 4 \log{\left(2 \right)}^{2}} + \frac{4 e \log{\left(2 \right)}^{2}}{- 4 \log{\left(2 \right)} \log{\left(5 \right)} + 4 \log{\left(2 \right)}^{2}} + \frac{2 \log{\left(5 \right)}}{- 4 \log{\left(2 \right)} \log{\left(5 \right)} + 4 \log{\left(2 \right)}^{2}} - \frac{\log{\left(5 \right)}}{- \log{\left(2 \right)} \log{\left(5 \right)} + \log{\left(2 \right)}^{2}} - \frac{3 \log{\left(2 \right)}}{- \log{\left(2 \right)} \log{\left(5 \right)} + \log{\left(2 \right)}^{2}} - \frac{4 e \log{\left(2 \right)} \log{\left(5 \right)}}{- 4 \log{\left(2 \right)} \log{\left(5 \right)} + 4 \log{\left(2 \right)}^{2}} - \frac{12 \log{\left(2 \right)} \log{\left(5 \right)}}{- 4 \log{\left(2 \right)} \log{\left(5 \right)} + 4 \log{\left(2 \right)}^{2}} − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 38 log ( 2 ) + − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 12 log ( 2 ) 2 + − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 4 e log ( 2 ) 2 + − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 2 log ( 5 ) − − log ( 2 ) log ( 5 ) + log ( 2 ) 2 log ( 5 ) − − log ( 2 ) log ( 5 ) + log ( 2 ) 2 3 log ( 2 ) − − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 4 e log ( 2 ) log ( 5 ) − − 4 log ( 2 ) log ( 5 ) + 4 log ( 2 ) 2 12 log ( 2 ) log ( 5 )
-log(5)/(log(2)^2 - log(2)*log(5)) - 3*log(2)/(log(2)^2 - log(2)*log(5)) + 2*log(5)/(4*log(2)^2 - 4*log(2)*log(5)) + 12*log(2)^2/(4*log(2)^2 - 4*log(2)*log(5)) + 38*log(2)/(4*log(2)^2 - 4*log(2)*log(5)) - 12*log(2)*log(5)/(4*log(2)^2 - 4*log(2)*log(5)) + 4*E*log(2)^2/(4*log(2)^2 - 4*log(2)*log(5)) - 4*E*log(2)*log(5)/(4*log(2)^2 - 4*log(2)*log(5))
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.