Tomamos como el límite
$$\lim_{x \to 2^+}\left(\frac{x^{2} + x}{2 x^{4} + \left(x^{5} + x^{3}\right)}\right)$$
cambiamos
$$\lim_{x \to 2^+}\left(\frac{x^{2} + x}{2 x^{4} + \left(x^{5} + x^{3}\right)}\right)$$
=
$$\lim_{x \to 2^+}\left(\frac{x \left(x + 1\right)}{x^{3} \left(x + 1\right)^{2}}\right)$$
=
$$\lim_{x \to 2^+}\left(\frac{1}{x^{2} \left(x + 1\right)}\right) = $$
$$\frac{1}{4 \left(1 + 2\right)} = $$
= 1/12
Entonces la respuesta definitiva es:
$$\lim_{x \to 2^+}\left(\frac{x^{2} + x}{2 x^{4} + \left(x^{5} + x^{3}\right)}\right) = \frac{1}{12}$$