Tenemos la indeterminación de tipo
0/0,
tal que el límite para el numerador es
$$\lim_{x \to 0^+}\left(- \left|{\sin{\left(2 x \right)} - 1}\right| + \left|{\sin{\left(2 x \right)} + 1}\right|\right) = 0$$
y el límite para el denominador es
$$\lim_{x \to 0^+} \tan{\left(x \right)} = 0$$
Vamos a probar las derivadas del numerador y denominador hasta eliminar la indeterminación.
$$\lim_{x \to 0^+}\left(\frac{- \left|{\sin{\left(2 x \right)} - 1}\right| + \left|{\sin{\left(2 x \right)} + 1}\right|}{\tan{\left(x \right)}}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(- \left|{\sin{\left(2 x \right)} - 1}\right| + \left|{\sin{\left(2 x \right)} + 1}\right|\right)}{\frac{d}{d x} \tan{\left(x \right)}}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\frac{2 \sin^{2}{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh{\left(2 \operatorname{im}{\left(x\right)} \right)} \cosh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} + 1 \right)} \frac{d}{d x} \operatorname{im}{\left(x\right)}}{\sin{\left(2 x \right)} + 1} - \frac{2 \sin{\left(2 \operatorname{re}{\left(x\right)} \right)} \cos{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh^{2}{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} + 1 \right)} \frac{d}{d x} \operatorname{re}{\left(x\right)}}{\sin{\left(2 x \right)} + 1} + \frac{2 \sin{\left(2 \operatorname{re}{\left(x\right)} \right)} \cos{\left(2 \operatorname{re}{\left(x\right)} \right)} \cosh^{2}{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} + 1 \right)} \frac{d}{d x} \operatorname{re}{\left(x\right)}}{\sin{\left(2 x \right)} + 1} + \frac{2 \sin{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} + 1 \right)} \frac{d}{d x} \operatorname{im}{\left(x\right)}}{\sin{\left(2 x \right)} + 1} + \frac{2 \cos^{2}{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh{\left(2 \operatorname{im}{\left(x\right)} \right)} \cosh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} + 1 \right)} \frac{d}{d x} \operatorname{im}{\left(x\right)}}{\sin{\left(2 x \right)} + 1} + \frac{2 \cos{\left(2 \operatorname{re}{\left(x\right)} \right)} \cosh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} + 1 \right)} \frac{d}{d x} \operatorname{re}{\left(x\right)}}{\sin{\left(2 x \right)} + 1} - \frac{2 \sin^{2}{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh{\left(2 \operatorname{im}{\left(x\right)} \right)} \cosh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} - 1 \right)} \frac{d}{d x} \operatorname{im}{\left(x\right)}}{\sin{\left(2 x \right)} - 1} + \frac{2 \sin{\left(2 \operatorname{re}{\left(x\right)} \right)} \cos{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh^{2}{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} - 1 \right)} \frac{d}{d x} \operatorname{re}{\left(x\right)}}{\sin{\left(2 x \right)} - 1} - \frac{2 \sin{\left(2 \operatorname{re}{\left(x\right)} \right)} \cos{\left(2 \operatorname{re}{\left(x\right)} \right)} \cosh^{2}{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} - 1 \right)} \frac{d}{d x} \operatorname{re}{\left(x\right)}}{\sin{\left(2 x \right)} - 1} + \frac{2 \sin{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} - 1 \right)} \frac{d}{d x} \operatorname{im}{\left(x\right)}}{\sin{\left(2 x \right)} - 1} - \frac{2 \cos^{2}{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh{\left(2 \operatorname{im}{\left(x\right)} \right)} \cosh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} - 1 \right)} \frac{d}{d x} \operatorname{im}{\left(x\right)}}{\sin{\left(2 x \right)} - 1} + \frac{2 \cos{\left(2 \operatorname{re}{\left(x\right)} \right)} \cosh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} - 1 \right)} \frac{d}{d x} \operatorname{re}{\left(x\right)}}{\sin{\left(2 x \right)} - 1}}{\tan^{2}{\left(x \right)} + 1}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\frac{2 \sin^{2}{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh{\left(2 \operatorname{im}{\left(x\right)} \right)} \cosh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} + 1 \right)} \frac{d}{d x} \operatorname{im}{\left(x\right)}}{\sin{\left(2 x \right)} + 1} - \frac{2 \sin{\left(2 \operatorname{re}{\left(x\right)} \right)} \cos{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh^{2}{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} + 1 \right)} \frac{d}{d x} \operatorname{re}{\left(x\right)}}{\sin{\left(2 x \right)} + 1} + \frac{2 \sin{\left(2 \operatorname{re}{\left(x\right)} \right)} \cos{\left(2 \operatorname{re}{\left(x\right)} \right)} \cosh^{2}{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} + 1 \right)} \frac{d}{d x} \operatorname{re}{\left(x\right)}}{\sin{\left(2 x \right)} + 1} + \frac{2 \sin{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} + 1 \right)} \frac{d}{d x} \operatorname{im}{\left(x\right)}}{\sin{\left(2 x \right)} + 1} + \frac{2 \cos^{2}{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh{\left(2 \operatorname{im}{\left(x\right)} \right)} \cosh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} + 1 \right)} \frac{d}{d x} \operatorname{im}{\left(x\right)}}{\sin{\left(2 x \right)} + 1} + \frac{2 \cos{\left(2 \operatorname{re}{\left(x\right)} \right)} \cosh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} + 1 \right)} \frac{d}{d x} \operatorname{re}{\left(x\right)}}{\sin{\left(2 x \right)} + 1} - \frac{2 \sin^{2}{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh{\left(2 \operatorname{im}{\left(x\right)} \right)} \cosh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} - 1 \right)} \frac{d}{d x} \operatorname{im}{\left(x\right)}}{\sin{\left(2 x \right)} - 1} + \frac{2 \sin{\left(2 \operatorname{re}{\left(x\right)} \right)} \cos{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh^{2}{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} - 1 \right)} \frac{d}{d x} \operatorname{re}{\left(x\right)}}{\sin{\left(2 x \right)} - 1} - \frac{2 \sin{\left(2 \operatorname{re}{\left(x\right)} \right)} \cos{\left(2 \operatorname{re}{\left(x\right)} \right)} \cosh^{2}{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} - 1 \right)} \frac{d}{d x} \operatorname{re}{\left(x\right)}}{\sin{\left(2 x \right)} - 1} + \frac{2 \sin{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} - 1 \right)} \frac{d}{d x} \operatorname{im}{\left(x\right)}}{\sin{\left(2 x \right)} - 1} - \frac{2 \cos^{2}{\left(2 \operatorname{re}{\left(x\right)} \right)} \sinh{\left(2 \operatorname{im}{\left(x\right)} \right)} \cosh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} - 1 \right)} \frac{d}{d x} \operatorname{im}{\left(x\right)}}{\sin{\left(2 x \right)} - 1} + \frac{2 \cos{\left(2 \operatorname{re}{\left(x\right)} \right)} \cosh{\left(2 \operatorname{im}{\left(x\right)} \right)} \operatorname{sign}{\left(\sin{\left(2 x \right)} - 1 \right)} \frac{d}{d x} \operatorname{re}{\left(x\right)}}{\sin{\left(2 x \right)} - 1}}{\tan^{2}{\left(x \right)} + 1}\right)$$
=
$$4$$
Como puedes ver, hemos aplicado el método de l'Hopital (utilizando la derivada del numerador y denominador) 1 vez (veces)