Tomamos como el límite
$$\lim_{x \to 2^+}\left(\frac{9 - x^{2}}{4 x + \left(x^{3} - 4 x^{2}\right)}\right)$$
cambiamos
$$\lim_{x \to 2^+}\left(\frac{9 - x^{2}}{4 x + \left(x^{3} - 4 x^{2}\right)}\right)$$
=
$$\lim_{x \to 2^+}\left(\frac{\left(-1\right) \left(x - 3\right) \left(x + 3\right)}{x \left(x - 2\right)^{2}}\right)$$
=
$$\lim_{x \to 2^+}\left(- \frac{\left(x - 3\right) \left(x + 3\right)}{x \left(x - 2\right)^{2}}\right) = $$
False
= oo
Entonces la respuesta definitiva es:
$$\lim_{x \to 2^+}\left(\frac{9 - x^{2}}{4 x + \left(x^{3} - 4 x^{2}\right)}\right) = \infty$$