Expresión a&¬cvc&(b&¬c)v(av¬b)&c
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$b \wedge c \wedge \neg c = \text{False}$$
$$\left(a \wedge \neg c\right) \vee \left(c \wedge \left(a \vee \neg b\right)\right) \vee \left(b \wedge c \wedge \neg c\right) = a \vee \left(c \wedge \neg b\right)$$
$$a \vee \left(c \wedge \neg b\right)$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$a \vee \left(c \wedge \neg b\right)$$
$$\left(a \vee c\right) \wedge \left(a \vee \neg b\right)$$
$$\left(a \vee c\right) \wedge \left(a \vee \neg b\right)$$
Ya está reducido a FND
$$a \vee \left(c \wedge \neg b\right)$$