Expresión abc∨¬abc∨¬a¬bc∨¬a¬b¬c
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\left(a \wedge b \wedge c\right) \vee \left(b \wedge c \wedge \neg a\right) \vee \left(c \wedge \neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg b \wedge \neg c\right) = \left(b \wedge c\right) \vee \left(\neg a \wedge \neg b\right)$$
$$\left(b \wedge c\right) \vee \left(\neg a \wedge \neg b\right)$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$\left(b \vee \neg a\right) \wedge \left(c \vee \neg b\right)$$
$$\left(b \wedge c\right) \vee \left(\neg a \wedge \neg b\right)$$
$$\left(b \vee \neg a\right) \wedge \left(b \vee \neg b\right) \wedge \left(c \vee \neg a\right) \wedge \left(c \vee \neg b\right)$$
(b∨(¬a))∧(b∨(¬b))∧(c∨(¬a))∧(c∨(¬b))
Ya está reducido a FND
$$\left(b \wedge c\right) \vee \left(\neg a \wedge \neg b\right)$$