Expresión abc+ab|c+a|bc+a|bc|
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\left(a \wedge b\right) \vee \left(a \wedge b \wedge c\right) = a \wedge b$$
$$\left(\left(a \wedge b\right) \vee \left(a \wedge b \wedge c\right)\right) | \left(a \vee c\right) | \left(a \vee \left(b \wedge c\right)\right) | \left(b \wedge c\right) = \neg a \vee \neg b \vee \neg c$$
$$\neg a \vee \neg b \vee \neg c$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 0 |
+---+---+---+--------+
$$\neg a \vee \neg b \vee \neg c$$
$$\neg a \vee \neg b \vee \neg c$$
Ya está reducido a FNC
$$\neg a \vee \neg b \vee \neg c$$
Ya está reducido a FND
$$\neg a \vee \neg b \vee \neg c$$