Expresión (¬abc)∨(abc)∨(bc)∨(a¬b¬c)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\left(b \wedge c\right) \vee \left(a \wedge b \wedge c\right) \vee \left(a \wedge \neg b \wedge \neg c\right) \vee \left(b \wedge c \wedge \neg a\right) = \left(a \vee c\right) \wedge \left(b \vee \neg c\right) \wedge \left(c \vee \neg b\right)$$
$$\left(a \vee c\right) \wedge \left(b \vee \neg c\right) \wedge \left(c \vee \neg b\right)$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$\left(b \wedge c\right) \vee \left(a \wedge \neg b \wedge \neg c\right)$$
$$\left(b \wedge c\right) \vee \left(c \wedge \neg c\right) \vee \left(a \wedge b \wedge c\right) \vee \left(a \wedge b \wedge \neg b\right) \vee \left(a \wedge c \wedge \neg c\right) \vee \left(a \wedge \neg b \wedge \neg c\right) \vee \left(b \wedge c \wedge \neg b\right) \vee \left(c \wedge \neg b \wedge \neg c\right)$$
(b∧c)∨(c∧(¬c))∨(a∧b∧c)∨(a∧b∧(¬b))∨(a∧c∧(¬c))∨(b∧c∧(¬b))∨(a∧(¬b)∧(¬c))∨(c∧(¬b)∧(¬c))
$$\left(a \vee c\right) \wedge \left(b \vee \neg c\right) \wedge \left(c \vee \neg b\right)$$
Ya está reducido a FNC
$$\left(a \vee c\right) \wedge \left(b \vee \neg c\right) \wedge \left(c \vee \neg b\right)$$