Expresión (abc)∨(a¬bc)∨(¬abc)∨(¬a¬bc)∨(¬a¬b¬c)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\left(a \wedge b \wedge c\right) \vee \left(a \wedge c \wedge \neg b\right) \vee \left(b \wedge c \wedge \neg a\right) \vee \left(c \wedge \neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg b \wedge \neg c\right) = c \vee \left(\neg a \wedge \neg b\right)$$
$$c \vee \left(\neg a \wedge \neg b\right)$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$c \vee \left(\neg a \wedge \neg b\right)$$
$$\left(c \vee \neg a\right) \wedge \left(c \vee \neg b\right)$$
$$\left(c \vee \neg a\right) \wedge \left(c \vee \neg b\right)$$
Ya está reducido a FND
$$c \vee \left(\neg a \wedge \neg b\right)$$