Expresión (¬a∨b)∧(a∨c)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(a∨c)∧(b∨¬a)=(a∧b)∨(c∧¬a)
(a∧b)∨(c∧¬a)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(a∧b)∨(c∧¬a)
Ya está reducido a FND
(a∧b)∨(c∧¬a)
(a∨c)∧(b∨¬a)
(a∨c)∧(a∨¬a)∧(b∨c)∧(b∨¬a)
(a∨c)∧(b∨c)∧(a∨(¬a))∧(b∨(¬a))