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Expresión abc=>ab+ac+bc

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    Solución

    Ha introducido [src]
    (a∧b∧c)⇒((a∧b)∨(a∧c)∨(b∧c))
    $$\left(a \wedge b \wedge c\right) \Rightarrow \left(\left(a \wedge b\right) \vee \left(a \wedge c\right) \vee \left(b \wedge c\right)\right)$$
    Solución detallada
    $$\left(a \wedge b \wedge c\right) \Rightarrow \left(\left(a \wedge b\right) \vee \left(a \wedge c\right) \vee \left(b \wedge c\right)\right) = 1$$
    Simplificación [src]
    1
    1
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    1
    1
    FNC [src]
    Ya está reducido a FNC
    1
    1
    FND [src]
    Ya está reducido a FND
    1
    1
    FNCD [src]
    1
    1