Sr Examen
Expresión b&av(not(a)vb)&b&c&(a¬(b))
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Solución
Ha introducido
[src]
(a∧b)∨(a∧b∧c∧(¬b)∧(b∨(¬a)))
$$\left(a \wedge b\right) \vee \left(a \wedge b \wedge c \wedge \neg b \wedge \left(b \vee \neg a\right)\right)$$
Solución detallada
$$a \wedge b \wedge c \wedge \neg b \wedge \left(b \vee \neg a\right) = \text{False}$$
$$\left(a \wedge b\right) \vee \left(a \wedge b \wedge c \wedge \neg b \wedge \left(b \vee \neg a\right)\right) = a \wedge b$$
$$\left(a \wedge b\right) \vee \left(a \wedge b \wedge c \wedge \neg b \wedge \left(b \vee \neg a\right)\right) = a \wedge b$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+