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Lógica matemática/ (x)v(xy)v(yz)v(x&-z)

Expresión (x)v(xy)v(yz)v(x&-z)

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    x∨(x∧y)∨(y∧z)∨(x∧(¬z))
    x∨(x∧y)∨(x∧¬z)∨(y∧z)x \vee \left(x \wedge y\right) \vee \left(x \wedge \neg z\right) \vee \left(y \wedge z\right)
    Solución detallada
    x∨(x∧y)∨(x∧¬z)∨(y∧z)=x∨(y∧z)x \vee \left(x \wedge y\right) \vee \left(x \wedge \neg z\right) \vee \left(y \wedge z\right) = x \vee \left(y \wedge z\right)
    Simplificación [src]
    x∨(y∧z)x \vee \left(y \wedge z\right) 
    x∨(y∧z)
    Tabla de verdad 
    +---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNCD [src]
    (x∨y)∧(x∨z)\left(x \vee y\right) \wedge \left(x \vee z\right) 
    (x∨y)∧(x∨z)
    FND [src]
    Ya está reducido a FND
    x∨(y∧z)x \vee \left(y \wedge z\right) 
    x∨(y∧z)
    FNC [src]
    (x∨y)∧(x∨z)\left(x \vee y\right) \wedge \left(x \vee z\right) 
    (x∨y)∧(x∨z)
    FNDP [src]
    x∨(y∧z)x \vee \left(y \wedge z\right) 
    x∨(y∧z)
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