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Lógica matemática/ (¬xy+xz)

Expresión (¬xy+xz)

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⌨

    Solución

    Ha introducido [src] 
    (x∧z)∨(y∧(¬x))
    $$\left(x \wedge z\right) \vee \left(y \wedge \neg x\right)$$
    Simplificación [src]
    $$\left(x \wedge z\right) \vee \left(y \wedge \neg x\right)$$ 
    (x∧z)∨(y∧(¬x))
    Tabla de verdad 
    +---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$\left(x \wedge z\right) \vee \left(y \wedge \neg x\right)$$ 
    (x∧z)∨(y∧(¬x))
    FNCD [src]
    $$\left(x \vee y\right) \wedge \left(z \vee \neg x\right)$$ 
    (x∨y)∧(z∨(¬x))
    FNC [src]
    $$\left(x \vee y\right) \wedge \left(x \vee \neg x\right) \wedge \left(y \vee z\right) \wedge \left(z \vee \neg x\right)$$ 
    (x∨y)∧(y∨z)∧(x∨(¬x))∧(z∨(¬x))
    FNDP [src]
    $$\left(x \wedge z\right) \vee \left(y \wedge \neg x\right)$$ 
    (x∧z)∨(y∧(¬x))
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