Expresión avb&a↓b&c&d
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
a∨(a∧b)=a(a∨(a∧b))↓(b∧c∧d)=¬a∧(¬b∨¬c∨¬d)
¬a∧(¬b∨¬c∨¬d)
Tabla de verdad
+---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 0 |
+---+---+---+---+--------+
Ya está reducido a FNC
¬a∧(¬b∨¬c∨¬d)
¬a∧(¬b∨¬c∨¬d)
(¬a∧¬b)∨(¬a∧¬c)∨(¬a∧¬d)
((¬a)∧(¬b))∨((¬a)∧(¬c))∨((¬a)∧(¬d))
(¬a∧¬b)∨(¬a∧¬c)∨(¬a∧¬d)
((¬a)∧(¬b))∨((¬a)∧(¬c))∨((¬a)∧(¬d))