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Expresión xy⇒z⇒(x⇒(y⇒z))
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Solución
Ha introducido
[src]
((x∧y)⇒z)⇒(x⇒(y⇒z))
$$\left(\left(x \wedge y\right) \Rightarrow z\right) \Rightarrow \left(x \Rightarrow \left(y \Rightarrow z\right)\right)$$
Solución detallada
$$\left(x \wedge y\right) \Rightarrow z = z \vee \neg x \vee \neg y$$
$$y \Rightarrow z = z \vee \neg y$$
$$x \Rightarrow \left(y \Rightarrow z\right) = z \vee \neg x \vee \neg y$$
$$\left(\left(x \wedge y\right) \Rightarrow z\right) \Rightarrow \left(x \Rightarrow \left(y \Rightarrow z\right)\right) = 1$$
$$y \Rightarrow z = z \vee \neg y$$
$$x \Rightarrow \left(y \Rightarrow z\right) = z \vee \neg x \vee \neg y$$
$$\left(\left(x \wedge y\right) \Rightarrow z\right) \Rightarrow \left(x \Rightarrow \left(y \Rightarrow z\right)\right) = 1$$
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+