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¿Cómo vas a descomponer esta sin(2*a)/((2*th(a))) expresión en fracciones?

Expresión a simplificar:

Solución

Ha introducido [src]
 sin(2*a)
---------
2*tanh(a)
$$\frac{\sin{\left(2 a \right)}}{2 \tanh{\left(a \right)}}$$
sin(2*a)/((2*tanh(a)))
Potencias [src]
   /   -2*I*a    2*I*a\ 
-I*\- e       + e     / 
------------------------
       4*tanh(a)        
$$- \frac{i \left(e^{2 i a} - e^{- 2 i a}\right)}{4 \tanh{\left(a \right)}}$$
-i*(-exp(-2*i*a) + exp(2*i*a))/(4*tanh(a))
Abrimos la expresión [src]
cos(a)*sin(a)
-------------
   tanh(a)   
$$\frac{\sin{\left(a \right)} \cos{\left(a \right)}}{\tanh{\left(a \right)}}$$
cos(a)*sin(a)/tanh(a)
Respuesta numérica [src]
0.5*sin(2*a)/tanh(a)
0.5*sin(2*a)/tanh(a)
Parte trigonométrica [src]
        1         
------------------
2*csc(2*a)*tanh(a)
$$\frac{1}{2 \tanh{\left(a \right)} \csc{\left(2 a \right)}}$$
        tan(a)       
---------------------
/       2   \        
\1 + tan (a)/*tanh(a)
$$\frac{\tan{\left(a \right)}}{\left(\tan^{2}{\left(a \right)} + 1\right) \tanh{\left(a \right)}}$$
           1           
-----------------------
     /      pi\        
2*sec|2*a - --|*tanh(a)
     \      2 /        
$$\frac{1}{2 \tanh{\left(a \right)} \sec{\left(2 a - \frac{\pi}{2} \right)}}$$
        cot(a)       
---------------------
/       2   \        
\1 + cot (a)/*tanh(a)
$$\frac{\cot{\left(a \right)}}{\left(\cot^{2}{\left(a \right)} + 1\right) \tanh{\left(a \right)}}$$
   /      pi\
cos|2*a - --|
   \      2 /
-------------
  2*tanh(a)  
$$\frac{\cos{\left(2 a - \frac{\pi}{2} \right)}}{2 \tanh{\left(a \right)}}$$
cos(2*a - pi/2)/(2*tanh(a))