Expresión del cuadrado perfecto
Expresemos el cuadrado perfecto del trinomio cuadrático
$$\left(x^{4} - 2 x^{2}\right) + 8$$
Para eso usemos la fórmula
$$a x^{4} + b x^{2} + c = a \left(m + x^{2}\right)^{2} + n$$
donde
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
En nuestro caso
$$a = 1$$
$$b = -2$$
$$c = 8$$
Entonces
$$m = -1$$
$$n = 7$$
Pues,
$$\left(x^{2} - 1\right)^{2} + 7$$
/ / / ___\\ / / ___\\\ / / / ___\\ / / ___\\\ / / / ___\\ / / ___\\\ / / / ___\\ / / ___\\\
| 3/4 |atan\\/ 7 /| 3/4 |atan\\/ 7 /|| | 3/4 |atan\\/ 7 /| 3/4 |atan\\/ 7 /|| | 3/4 |atan\\/ 7 /| 3/4 |atan\\/ 7 /|| | 3/4 |atan\\/ 7 /| 3/4 |atan\\/ 7 /||
|x + 2 *cos|-----------| + I*2 *sin|-----------||*|x + 2 *cos|-----------| - I*2 *sin|-----------||*|x + - 2 *cos|-----------| + I*2 *sin|-----------||*|x + - 2 *cos|-----------| - I*2 *sin|-----------||
\ \ 2 / \ 2 // \ \ 2 / \ 2 // \ \ 2 / \ 2 // \ \ 2 / \ 2 //
$$\left(x + \left(2^{\frac{3}{4}} \cos{\left(\frac{\operatorname{atan}{\left(\sqrt{7} \right)}}{2} \right)} - 2^{\frac{3}{4}} i \sin{\left(\frac{\operatorname{atan}{\left(\sqrt{7} \right)}}{2} \right)}\right)\right) \left(x + \left(2^{\frac{3}{4}} \cos{\left(\frac{\operatorname{atan}{\left(\sqrt{7} \right)}}{2} \right)} + 2^{\frac{3}{4}} i \sin{\left(\frac{\operatorname{atan}{\left(\sqrt{7} \right)}}{2} \right)}\right)\right) \left(x + \left(- 2^{\frac{3}{4}} \cos{\left(\frac{\operatorname{atan}{\left(\sqrt{7} \right)}}{2} \right)} + 2^{\frac{3}{4}} i \sin{\left(\frac{\operatorname{atan}{\left(\sqrt{7} \right)}}{2} \right)}\right)\right) \left(x + \left(- 2^{\frac{3}{4}} \cos{\left(\frac{\operatorname{atan}{\left(\sqrt{7} \right)}}{2} \right)} - 2^{\frac{3}{4}} i \sin{\left(\frac{\operatorname{atan}{\left(\sqrt{7} \right)}}{2} \right)}\right)\right)$$
(((x + 2^(3/4)*cos(atan(sqrt(7))/2) + i*2^(3/4)*sin(atan(sqrt(7))/2))*(x + 2^(3/4)*cos(atan(sqrt(7))/2) - i*2^(3/4)*sin(atan(sqrt(7))/2)))*(x - 2^(3/4)*cos(atan(sqrt(7))/2) + i*2^(3/4)*sin(atan(sqrt(7))/2)))*(x - 2^(3/4)*cos(atan(sqrt(7))/2) - i*2^(3/4)*sin(atan(sqrt(7))/2))