Sr Examen

Ecuación diferencial dy/dx=-2/y-3y/2x

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
d             2     3*x*y(x)
--(y(x)) = - ---- - --------
dx           y(x)      2    
$$\frac{d}{d x} y{\left(x \right)} = - \frac{3 x y{\left(x \right)}}{2} - \frac{2}{y{\left(x \right)}}$$
y' = -3*x*y/2 - 2/y
Respuesta [src]
                                         /         /  3    60\        /  3    12\\                       /               /  3    60\      /3   180\\        
                                         |       4*|- - + ---|   3*C1*|- - + ---||                       |             8*|- - + ---|   16*|- - ---||        
                                         |         |  2     4|        |  2     4||                       |               |  2     4|      |2     4||        
             2 /   4    3*C1\          4 |9*C1     \      C1 /        \      C1 /|    3 /  3    12\    5 |  63   396     \      C1 /      \    C1 /|        
            x *|- --- - ----|         x *|---- - ------------- - ----------------|   x *|- - + ---|   x *|- -- - --- - ------------- + ------------|        
               |    3    2  |            | 2            3               2        |      |  2     4|      |  2      4          4              4     |        
               \  C1        /   2*x      \            C1                         /      \      C1 /      \       C1         C1             C1      /    / 6\
y(x) = C1 + ----------------- - --- + -------------------------------------------- - -------------- + ---------------------------------------------- + O\x /
                    2            C1                        24                             3*C1                            120*C1                            
$$y{\left(x \right)} = - \frac{2 x}{C_{1}} - \frac{x^{3} \left(- \frac{3}{2} + \frac{12}{C_{1}^{4}}\right)}{3 C_{1}} + \frac{x^{5} \left(- \frac{63}{2} - \frac{8 \left(- \frac{3}{2} + \frac{60}{C_{1}^{4}}\right)}{C_{1}^{4}} + \frac{16 \left(\frac{3}{2} - \frac{180}{C_{1}^{4}}\right)}{C_{1}^{4}} - \frac{396}{C_{1}^{4}}\right)}{120 C_{1}} + \frac{x^{2} \left(- \frac{3 C_{1}}{2} - \frac{4}{C_{1}^{3}}\right)}{2} + \frac{x^{4} \left(- \frac{3 C_{1} \left(- \frac{3}{2} + \frac{12}{C_{1}^{4}}\right)}{2} + \frac{9 C_{1}}{2} - \frac{4 \left(- \frac{3}{2} + \frac{60}{C_{1}^{4}}\right)}{C_{1}^{3}}\right)}{24} + C_{1} + O\left(x^{6}\right)$$
Gráfico para el problema de Cauchy
Clasificación
1st power series
lie group
Respuesta numérica [src]
(x, y):
(-10.0, 0.75)
(-7.777777777777778, 4831372980269.227)
(-5.555555555555555, 2.1630132052259127e+22)
(-3.333333333333333, 5.875590978999558e+28)
(-1.1111111111111107, 9.683842558381182e+31)
(1.1111111111111107, 9.683842226890383e+31)
(3.333333333333334, 5.8755907516326435e+28)
(5.555555555555557, 2.1630140157422874e+22)
(7.777777777777779, 4831378988528.616)
(10.0, 0.5430814441523724)
(10.0, 0.5430814441523724)