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Ecuación diferencial dx*(2*x*y^2-3)+dy*(2*x^2*y+4)=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
       d               2         2 d                
-3 + 4*--(y(x)) + 2*x*y (x) + 2*x *--(y(x))*y(x) = 0
       dx                          dx               
$$2 x^{2} y{\left(x \right)} \frac{d}{d x} y{\left(x \right)} + 2 x y^{2}{\left(x \right)} + 4 \frac{d}{d x} y{\left(x \right)} - 3 = 0$$
2*x^2*y*y' + 2*x*y^2 + 4*y' - 3 = 0
Respuesta [src]
               __________________
              /        3       2 
       -2 + \/  4 + 3*x  + C1*x  
y(x) = --------------------------
                    2            
                   x             
$$y{\left(x \right)} = \frac{\sqrt{C_{1} x^{2} + 3 x^{3} + 4} - 2}{x^{2}}$$
               __________________
              /        3       2 
       -2 - \/  4 + 3*x  + C1*x  
y(x) = --------------------------
                    2            
                   x             
$$y{\left(x \right)} = \frac{- \sqrt{C_{1} x^{2} + 3 x^{3} + 4} - 2}{x^{2}}$$
Clasificación
1st exact
1st power series
lie group
1st exact Integral