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Ecuación diferencial y'''-4*y''+5*y'-2*y=(16-2*x)*exp(-x)

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
      2                                 3                       
     d                     d           d                      -x
- 4*---(y(x)) - 2*y(x) + 5*--(y(x)) + ---(y(x)) = (16 - 2*x)*e  
      2                    dx           3                       
    dx                                dx                        
$$- 2 y{\left(x \right)} + 5 \frac{d}{d x} y{\left(x \right)} - 4 \frac{d^{2}}{d x^{2}} y{\left(x \right)} + \frac{d^{3}}{d x^{3}} y{\left(x \right)} = \left(16 - 2 x\right) e^{- x}$$
-2*y + 5*y' - 4*y'' + y''' = (16 - 2*x)*exp(-x)
Respuesta [src]
                                               -x
           2*x                x   (-20 + 3*x)*e  
y(x) = C3*e    + (C1 + C2*x)*e  + ---------------
                                         18      
$$y{\left(x \right)} = C_{3} e^{2 x} + \left(C_{1} + C_{2} x\right) e^{x} + \frac{\left(3 x - 20\right) e^{- x}}{18}$$
Clasificación
nth linear constant coeff undetermined coefficients
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