Sr Examen
Ecuación diferencial cos^2ydx+sin^2x
El profesor se sorprenderá mucho al ver tu solución correcta😉
⌨
Solución
Ha introducido
[src]
2
2 sin (x)
cos (y(x)) + ------- = 0
dx
$$\cos^{2}{\left(y{\left(x \right)} \right)} + \frac{\sin^{2}{\left(x \right)}}{dx} = 0$$
cos(y)^2 + sin(x)^2/dx = 0
Respuesta
[src]
/ _____ \
| / -1 |
y(x) = - acos|- / --- *sin(x)| + 2*pi
\ \/ dx /
$$y{\left(x \right)} = - \operatorname{acos}{\left(- \sqrt{- \frac{1}{dx}} \sin{\left(x \right)} \right)} + 2 \pi$$
/ _____ \
| / -1 |
y(x) = - acos| / --- *sin(x)| + 2*pi
\\/ dx /
$$y{\left(x \right)} = - \operatorname{acos}{\left(\sqrt{- \frac{1}{dx}} \sin{\left(x \right)} \right)} + 2 \pi$$
/ _____ \
| / -1 |
y(x) = acos|- / --- *sin(x)|
\ \/ dx /
$$y{\left(x \right)} = \operatorname{acos}{\left(- \sqrt{- \frac{1}{dx}} \sin{\left(x \right)} \right)}$$
/ _____ \
| / -1 |
y(x) = acos| / --- *sin(x)|
\\/ dx /
$$y{\left(x \right)} = \operatorname{acos}{\left(\sqrt{- \frac{1}{dx}} \sin{\left(x \right)} \right)}$$
Clasificación
nth algebraic
nth algebraic Integral