El profesor se sorprenderá mucho al ver tu solución correcta😉
/7*4200 \ |------*3| | 10 | |--------| \ 10 / 20 84 = ----------*log(2)*60 - -- - 20 21 x
a1 = 1
b1 = 1/(104 - 2520*log(2))
a2 = 1
b2 = -x/20
-x/20 = 1/104+1/2520*log+1/2)
x = 1/(104 - 2520*log(2)) / (-1/20)
suma
5 -------------------- 2*(-13 + 315*log(2))
=
5 -------------------- 2*(-13 + 315*log(2))
producto
5 -------------------- 2*(-13 + 315*log(2))
=
5 -------------------- 2*(-13 + 315*log(2))
5/(2*(-13 + 315*log(2)))
5 x1 = -------------------- 2*(-13 + 315*log(2))
x1 = 5/(2*(-13 + 315*log(2)))