x=2(cost+ln(tg(t/2))) la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
Tenemos la ecuación:
x=2(log(tan(2t))+cos(t))cambiamos:
x=2log(tan(2t))+2cos(t)Abrimos los paréntesis en el miembro derecho de la ecuación
x = 2*cost + 2*logtan+t/2)
Obtenemos la respuesta: x = 2*cos(t) + 2*log(tan(t/2))
Suma y producto de raíces
[src]
/| /t\|\ / / /t\\ \
2*log||tan|-||| + I*|2*arg|tan|-|| - 2*sin(re(t))*sinh(im(t))| + 2*cos(re(t))*cosh(im(t))
\| \2/|/ \ \ \2// /
i(−2sin(re(t))sinh(im(t))+2arg(tan(2t)))+2log(tan(2t))+2cos(re(t))cosh(im(t))
/| /t\|\ / / /t\\ \
2*log||tan|-||| + I*|2*arg|tan|-|| - 2*sin(re(t))*sinh(im(t))| + 2*cos(re(t))*cosh(im(t))
\| \2/|/ \ \ \2// /
i(−2sin(re(t))sinh(im(t))+2arg(tan(2t)))+2log(tan(2t))+2cos(re(t))cosh(im(t))
/| /t\|\ / / /t\\ \
2*log||tan|-||| + I*|2*arg|tan|-|| - 2*sin(re(t))*sinh(im(t))| + 2*cos(re(t))*cosh(im(t))
\| \2/|/ \ \ \2// /
i(−2sin(re(t))sinh(im(t))+2arg(tan(2t)))+2log(tan(2t))+2cos(re(t))cosh(im(t))
/| /t\|\ / / /t\\ \
2*log||tan|-||| + I*|2*arg|tan|-|| - 2*sin(re(t))*sinh(im(t))| + 2*cos(re(t))*cosh(im(t))
\| \2/|/ \ \ \2// /
i(−2sin(re(t))sinh(im(t))+2arg(tan(2t)))+2log(tan(2t))+2cos(re(t))cosh(im(t))
2*log(Abs(tan(t/2))) + i*(2*arg(tan(t/2)) - 2*sin(re(t))*sinh(im(t))) + 2*cos(re(t))*cosh(im(t))
/| /t\|\ / / /t\\ \
x1 = 2*log||tan|-||| + I*|2*arg|tan|-|| - 2*sin(re(t))*sinh(im(t))| + 2*cos(re(t))*cosh(im(t))
\| \2/|/ \ \ \2// /
x1=i(−2sin(re(t))sinh(im(t))+2arg(tan(2t)))+2log(tan(2t))+2cos(re(t))cosh(im(t))
x1 = i*(-2*sin(re(t))*sinh(im(t)) + 2*arg(tan(t/2))) + 2*log(Abs(tan(t/2))) + 2*cos(re(t))*cosh(im(t))