ln(x)*10^6=(ln(n))^y la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
Tenemos la ecuación:
1000000log(x)=log(n)yo
−log(n)y+1000000log(x)=0o
−log(n)y=−1000000log(x)o
log(n)y=1000000log(x)- es la ecuación exponencial más simple
Sustituimos
v=log(n)yobtendremos
v−1000000log(x)=0o
v−1000000log(x)=0hacemos cambio inverso
log(n)y=vo
y=log(log(n))log(v)Entonces la respuesta definitiva es
y1=log(log(n))log(1000000log(x))=log(log(n))log(1000000log(x))
Suma y producto de raíces
[src]
/log(1000000*log(x))\ /log(1000000*log(x))\
I*im|-------------------| + re|-------------------|
\ log(log(n)) / \ log(log(n)) /
re(log(log(n))log(1000000log(x)))+iim(log(log(n))log(1000000log(x)))
/log(1000000*log(x))\ /log(1000000*log(x))\
I*im|-------------------| + re|-------------------|
\ log(log(n)) / \ log(log(n)) /
re(log(log(n))log(1000000log(x)))+iim(log(log(n))log(1000000log(x)))
/log(1000000*log(x))\ /log(1000000*log(x))\
I*im|-------------------| + re|-------------------|
\ log(log(n)) / \ log(log(n)) /
re(log(log(n))log(1000000log(x)))+iim(log(log(n))log(1000000log(x)))
/log(1000000*log(x))\ /log(1000000*log(x))\
I*im|-------------------| + re|-------------------|
\ log(log(n)) / \ log(log(n)) /
re(log(log(n))log(1000000log(x)))+iim(log(log(n))log(1000000log(x)))
i*im(log(1000000*log(x))/log(log(n))) + re(log(1000000*log(x))/log(log(n)))
/log(1000000*log(x))\ /log(1000000*log(x))\
y1 = I*im|-------------------| + re|-------------------|
\ log(log(n)) / \ log(log(n)) /
y1=re(log(log(n))log(1000000log(x)))+iim(log(log(n))log(1000000log(x)))
y1 = re(log(1000000*log(x))/log(log(n))) + i*im(log(1000000*log(x))/log(log(n)))