El gráfico de la función cruce el eje X con f = 0
o sea hay que resolver la ecuación:
$$\sqrt{25 - x^{2}} + \frac{7}{x - 5} = 0$$
Resolvermos esta ecuaciónPuntos de cruce con el eje X:
Solución analítica$$x_{1} = - \frac{\sqrt{\frac{98}{3 \sqrt[3]{\frac{49 \sqrt{48273}}{36} + \frac{1225}{4}}} + 2 \sqrt[3]{\frac{49 \sqrt{48273}}{36} + \frac{1225}{4}} + 25}}{2} + \frac{5}{2} + \frac{\sqrt{- 2 \sqrt[3]{\frac{49 \sqrt{48273}}{36} + \frac{1225}{4}} - \frac{98}{3 \sqrt[3]{\frac{49 \sqrt{48273}}{36} + \frac{1225}{4}}} + \frac{250}{\sqrt{\frac{98}{3 \sqrt[3]{\frac{49 \sqrt{48273}}{36} + \frac{1225}{4}}} + 2 \sqrt[3]{\frac{49 \sqrt{48273}}{36} + \frac{1225}{4}} + 25}} + 50}}{2}$$
$$x_{2} = - \frac{\sqrt{- 2 \sqrt[3]{\frac{49 \sqrt{48273}}{36} + \frac{1225}{4}} - \frac{98}{3 \sqrt[3]{\frac{49 \sqrt{48273}}{36} + \frac{1225}{4}}} + \frac{250}{\sqrt{\frac{98}{3 \sqrt[3]{\frac{49 \sqrt{48273}}{36} + \frac{1225}{4}}} + 2 \sqrt[3]{\frac{49 \sqrt{48273}}{36} + \frac{1225}{4}} + 25}} + 50}}{2} - \frac{\sqrt{\frac{98}{3 \sqrt[3]{\frac{49 \sqrt{48273}}{36} + \frac{1225}{4}}} + 2 \sqrt[3]{\frac{49 \sqrt{48273}}{36} + \frac{1225}{4}} + 25}}{2} + \frac{5}{2}$$
Solución numérica$$x_{1} = 3.18417620473298$$
$$x_{2} = -4.95026151013494$$