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log(8*x^2+7)*1/log(11)-log(x^2+x+1)*1/log(11)>=log(x*1/(x+5)+7)*1/log(11) desigualdades

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Solución

Ha introducido [src]
                                      /  x      \
   /   2    \      / 2        \    log|----- + 7|
log\8*x  + 7/   log\x  + x + 1/       \x + 5    /
------------- - --------------- >= --------------
   log(11)          log(11)           log(11)    
$$\frac{\log{\left(8 x^{2} + 7 \right)}}{\log{\left(11 \right)}} - \frac{\log{\left(\left(x^{2} + x\right) + 1 \right)}}{\log{\left(11 \right)}} \geq \frac{\log{\left(\frac{x}{x + 5} + 7 \right)}}{\log{\left(11 \right)}}$$
log(8*x^2 + 7)/log(11) - log(x^2 + x + 1)/log(11) >= log(x/(x + 5) + 7)/log(11)