3 ----------- > |x + 2| |x + 3| - 1
3/(|x + 3| - 1) > |x + 2|
___ (-5, -4) U (-2, -2 + \/ 3 )
x in Union(Interval.open(-5, -4), Interval.open(-2, -2 + sqrt(3)))
/ / ___\\ Or\And(-5 < x, x < -4), And\-2 < x, x < -2 + \/ 3 //
((-5 < x)∧(x < -4))∨((-2 < x)∧(x < -2 + sqrt(3)))