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(5x-3)^2/(x-2)>=(9-30*x+25*x)/(14-9*x+x*x) desigualdades

En la desigualdad la incógnita

Solución

Ha introducido [src]
         2                   
(5*x - 3)     9 - 30*x + 25*x
---------- >= ---------------
  x - 2        14 - 9*x + x*x
$$\frac{\left(5 x - 3\right)^{2}}{x - 2} \geq \frac{25 x + \left(9 - 30 x\right)}{x x + \left(14 - 9 x\right)}$$
(5*x - 3)^2/(x - 2) >= (25*x + 9 - 30*x)/(x*x + 14 - 9*x)
Solución de la desigualdad en el gráfico
Respuesta rápida [src]
  /   /            /    3        2                \       \                    \
Or\And\x <= CRootOf\25*x  - 205*x  + 224*x - 72, 0/, 2 < x/, And(7 < x, x < oo)/
$$\left(x \leq \operatorname{CRootOf} {\left(25 x^{3} - 205 x^{2} + 224 x - 72, 0\right)} \wedge 2 < x\right) \vee \left(7 < x \wedge x < \infty\right)$$
((7 < x)∧(x < oo))∨((2 < x)∧(x <= CRootOf(25*x^3 - 205*x^2 + 224*x - 72, 0)))
Respuesta rápida 2 [src]
           /    3        2                \           
(2, CRootOf\25*x  - 205*x  + 224*x - 72, 0/] U (7, oo)
$$x\ in\ \left(2, \operatorname{CRootOf} {\left(25 x^{3} - 205 x^{2} + 224 x - 72, 0\right)}\right] \cup \left(7, \infty\right)$$
x in Union(Interval.Lopen(2, CRootOf(25*x^3 - 205*x^2 + 224*x - 72, 0)), Interval.open(7, oo))