Usamos la integración por partes:
∫ u dv = u v − ∫ v du \int \operatorname{u} \operatorname{dv}
= \operatorname{u}\operatorname{v} -
\int \operatorname{v} \operatorname{du} ∫ u dv = u v − ∫ v du
que u ( x ) = x 2 u{\left(x \right)} = x^{2} u ( x ) = x 2 y que dv ( x ) = cos ( 3 x 2 + 5 ) \operatorname{dv}{\left(x \right)} = \cos{\left(3 x^{2} + 5 \right)} dv ( x ) = cos ( 3 x 2 + 5 ) .
Entonces du ( x ) = 2 x \operatorname{du}{\left(x \right)} = 2 x du ( x ) = 2 x .
Para buscar v ( x ) v{\left(x \right)} v ( x ) :
FresnelCRule(a=3, b=0, c=5, context=cos(3*x**2 + 5), symbol=x)
Ahora resolvemos podintegral.
La integral del producto de una función por una constante es la constante por la integral de esta función:
∫ 6 π x ( cos ( 5 ) C ( 6 x π ) − sin ( 5 ) S ( 6 x π ) ) 3 d x = 6 π ∫ x ( cos ( 5 ) C ( 6 x π ) − sin ( 5 ) S ( 6 x π ) ) d x 3 \int \frac{\sqrt{6} \sqrt{\pi} x \left(\cos{\left(5 \right)} C\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right) - \sin{\left(5 \right)} S\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right)\right)}{3}\, dx = \frac{\sqrt{6} \sqrt{\pi} \int x \left(\cos{\left(5 \right)} C\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right) - \sin{\left(5 \right)} S\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right)\right)\, dx}{3} ∫ 3 6 π x ( c o s ( 5 ) C ( π 6 x ) − s i n ( 5 ) S ( π 6 x ) ) d x = 3 6 π ∫ x ( c o s ( 5 ) C ( π 6 x ) − s i n ( 5 ) S ( π 6 x ) ) d x
Vuelva a escribir el integrando:
x ( cos ( 5 ) C ( 6 x π ) − sin ( 5 ) S ( 6 x π ) ) = x cos ( 5 ) C ( 6 x π ) − x sin ( 5 ) S ( 6 x π ) x \left(\cos{\left(5 \right)} C\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right) - \sin{\left(5 \right)} S\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right)\right) = x \cos{\left(5 \right)} C\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right) - x \sin{\left(5 \right)} S\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right) x ( cos ( 5 ) C ( π 6 x ) − sin ( 5 ) S ( π 6 x ) ) = x cos ( 5 ) C ( π 6 x ) − x sin ( 5 ) S ( π 6 x )
Integramos término a término:
La integral del producto de una función por una constante es la constante por la integral de esta función:
∫ x cos ( 5 ) C ( 6 x π ) d x = cos ( 5 ) ∫ x C ( 6 x π ) d x \int x \cos{\left(5 \right)} C\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right)\, dx = \cos{\left(5 \right)} \int x C\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right)\, dx ∫ x cos ( 5 ) C ( π 6 x ) d x = cos ( 5 ) ∫ x C ( π 6 x ) d x
No puedo encontrar los pasos en la búsqueda de esta integral.
Pero la integral
6 x 3 Γ ( 1 4 ) Γ ( 3 4 ) 2 F 3 ( 1 4 , 3 4 1 2 , 5 4 , 7 4 | − 9 x 4 4 ) 16 π Γ ( 5 4 ) Γ ( 7 4 ) \frac{\sqrt{6} x^{3} \Gamma\left(\frac{1}{4}\right) \Gamma\left(\frac{3}{4}\right) {{}_{2}F_{3}\left(\begin{matrix} \frac{1}{4}, \frac{3}{4} \\ \frac{1}{2}, \frac{5}{4}, \frac{7}{4} \end{matrix}\middle| {- \frac{9 x^{4}}{4}} \right)}}{16 \sqrt{\pi} \Gamma\left(\frac{5}{4}\right) \Gamma\left(\frac{7}{4}\right)} 16 π Γ ( 4 5 ) Γ ( 4 7 ) 6 x 3 Γ ( 4 1 ) Γ ( 4 3 ) 2 F 3 ( 4 1 , 4 3 2 1 , 4 5 , 4 7 − 4 9 x 4 )
Por lo tanto, el resultado es: 6 x 3 cos ( 5 ) Γ ( 1 4 ) Γ ( 3 4 ) 2 F 3 ( 1 4 , 3 4 1 2 , 5 4 , 7 4 | − 9 x 4 4 ) 16 π Γ ( 5 4 ) Γ ( 7 4 ) \frac{\sqrt{6} x^{3} \cos{\left(5 \right)} \Gamma\left(\frac{1}{4}\right) \Gamma\left(\frac{3}{4}\right) {{}_{2}F_{3}\left(\begin{matrix} \frac{1}{4}, \frac{3}{4} \\ \frac{1}{2}, \frac{5}{4}, \frac{7}{4} \end{matrix}\middle| {- \frac{9 x^{4}}{4}} \right)}}{16 \sqrt{\pi} \Gamma\left(\frac{5}{4}\right) \Gamma\left(\frac{7}{4}\right)} 16 π Γ ( 4 5 ) Γ ( 4 7 ) 6 x 3 c o s ( 5 ) Γ ( 4 1 ) Γ ( 4 3 ) 2 F 3 ( 4 1 , 4 3 2 1 , 4 5 , 4 7 − 4 9 x 4 )
La integral del producto de una función por una constante es la constante por la integral de esta función:
∫ ( − x sin ( 5 ) S ( 6 x π ) ) d x = − sin ( 5 ) ∫ x S ( 6 x π ) d x \int \left(- x \sin{\left(5 \right)} S\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right)\right)\, dx = - \sin{\left(5 \right)} \int x S\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right)\, dx ∫ ( − x sin ( 5 ) S ( π 6 x ) ) d x = − sin ( 5 ) ∫ x S ( π 6 x ) d x
No puedo encontrar los pasos en la búsqueda de esta integral.
Pero la integral
3 6 x 5 Γ ( 3 4 ) Γ ( 5 4 ) 2 F 3 ( 3 4 , 5 4 3 2 , 7 4 , 9 4 | − 9 x 4 4 ) 16 π Γ ( 7 4 ) Γ ( 9 4 ) \frac{3 \sqrt{6} x^{5} \Gamma\left(\frac{3}{4}\right) \Gamma\left(\frac{5}{4}\right) {{}_{2}F_{3}\left(\begin{matrix} \frac{3}{4}, \frac{5}{4} \\ \frac{3}{2}, \frac{7}{4}, \frac{9}{4} \end{matrix}\middle| {- \frac{9 x^{4}}{4}} \right)}}{16 \sqrt{\pi} \Gamma\left(\frac{7}{4}\right) \Gamma\left(\frac{9}{4}\right)} 16 π Γ ( 4 7 ) Γ ( 4 9 ) 3 6 x 5 Γ ( 4 3 ) Γ ( 4 5 ) 2 F 3 ( 4 3 , 4 5 2 3 , 4 7 , 4 9 − 4 9 x 4 )
Por lo tanto, el resultado es: − 3 6 x 5 sin ( 5 ) Γ ( 3 4 ) Γ ( 5 4 ) 2 F 3 ( 3 4 , 5 4 3 2 , 7 4 , 9 4 | − 9 x 4 4 ) 16 π Γ ( 7 4 ) Γ ( 9 4 ) - \frac{3 \sqrt{6} x^{5} \sin{\left(5 \right)} \Gamma\left(\frac{3}{4}\right) \Gamma\left(\frac{5}{4}\right) {{}_{2}F_{3}\left(\begin{matrix} \frac{3}{4}, \frac{5}{4} \\ \frac{3}{2}, \frac{7}{4}, \frac{9}{4} \end{matrix}\middle| {- \frac{9 x^{4}}{4}} \right)}}{16 \sqrt{\pi} \Gamma\left(\frac{7}{4}\right) \Gamma\left(\frac{9}{4}\right)} − 16 π Γ ( 4 7 ) Γ ( 4 9 ) 3 6 x 5 s i n ( 5 ) Γ ( 4 3 ) Γ ( 4 5 ) 2 F 3 ( 4 3 , 4 5 2 3 , 4 7 , 4 9 − 4 9 x 4 )
El resultado es: − 3 6 x 5 sin ( 5 ) Γ ( 3 4 ) Γ ( 5 4 ) 2 F 3 ( 3 4 , 5 4 3 2 , 7 4 , 9 4 | − 9 x 4 4 ) 16 π Γ ( 7 4 ) Γ ( 9 4 ) + 6 x 3 cos ( 5 ) Γ ( 1 4 ) Γ ( 3 4 ) 2 F 3 ( 1 4 , 3 4 1 2 , 5 4 , 7 4 | − 9 x 4 4 ) 16 π Γ ( 5 4 ) Γ ( 7 4 ) - \frac{3 \sqrt{6} x^{5} \sin{\left(5 \right)} \Gamma\left(\frac{3}{4}\right) \Gamma\left(\frac{5}{4}\right) {{}_{2}F_{3}\left(\begin{matrix} \frac{3}{4}, \frac{5}{4} \\ \frac{3}{2}, \frac{7}{4}, \frac{9}{4} \end{matrix}\middle| {- \frac{9 x^{4}}{4}} \right)}}{16 \sqrt{\pi} \Gamma\left(\frac{7}{4}\right) \Gamma\left(\frac{9}{4}\right)} + \frac{\sqrt{6} x^{3} \cos{\left(5 \right)} \Gamma\left(\frac{1}{4}\right) \Gamma\left(\frac{3}{4}\right) {{}_{2}F_{3}\left(\begin{matrix} \frac{1}{4}, \frac{3}{4} \\ \frac{1}{2}, \frac{5}{4}, \frac{7}{4} \end{matrix}\middle| {- \frac{9 x^{4}}{4}} \right)}}{16 \sqrt{\pi} \Gamma\left(\frac{5}{4}\right) \Gamma\left(\frac{7}{4}\right)} − 16 π Γ ( 4 7 ) Γ ( 4 9 ) 3 6 x 5 s i n ( 5 ) Γ ( 4 3 ) Γ ( 4 5 ) 2 F 3 ( 4 3 , 4 5 2 3 , 4 7 , 4 9 − 4 9 x 4 ) + 16 π Γ ( 4 5 ) Γ ( 4 7 ) 6 x 3 c o s ( 5 ) Γ ( 4 1 ) Γ ( 4 3 ) 2 F 3 ( 4 1 , 4 3 2 1 , 4 5 , 4 7 − 4 9 x 4 )
Por lo tanto, el resultado es: 6 π ( − 3 6 x 5 sin ( 5 ) Γ ( 3 4 ) Γ ( 5 4 ) 2 F 3 ( 3 4 , 5 4 3 2 , 7 4 , 9 4 | − 9 x 4 4 ) 16 π Γ ( 7 4 ) Γ ( 9 4 ) + 6 x 3 cos ( 5 ) Γ ( 1 4 ) Γ ( 3 4 ) 2 F 3 ( 1 4 , 3 4 1 2 , 5 4 , 7 4 | − 9 x 4 4 ) 16 π Γ ( 5 4 ) Γ ( 7 4 ) ) 3 \frac{\sqrt{6} \sqrt{\pi} \left(- \frac{3 \sqrt{6} x^{5} \sin{\left(5 \right)} \Gamma\left(\frac{3}{4}\right) \Gamma\left(\frac{5}{4}\right) {{}_{2}F_{3}\left(\begin{matrix} \frac{3}{4}, \frac{5}{4} \\ \frac{3}{2}, \frac{7}{4}, \frac{9}{4} \end{matrix}\middle| {- \frac{9 x^{4}}{4}} \right)}}{16 \sqrt{\pi} \Gamma\left(\frac{7}{4}\right) \Gamma\left(\frac{9}{4}\right)} + \frac{\sqrt{6} x^{3} \cos{\left(5 \right)} \Gamma\left(\frac{1}{4}\right) \Gamma\left(\frac{3}{4}\right) {{}_{2}F_{3}\left(\begin{matrix} \frac{1}{4}, \frac{3}{4} \\ \frac{1}{2}, \frac{5}{4}, \frac{7}{4} \end{matrix}\middle| {- \frac{9 x^{4}}{4}} \right)}}{16 \sqrt{\pi} \Gamma\left(\frac{5}{4}\right) \Gamma\left(\frac{7}{4}\right)}\right)}{3} 3 6 π − 16 π Γ ( 4 7 ) Γ ( 4 9 ) 3 6 x 5 s i n ( 5 ) Γ ( 4 3 ) Γ ( 4 5 ) 2 F 3 ( 4 3 , 4 5 2 3 , 4 7 , 4 9 − 4 9 x 4 ) + 16 π Γ ( 4 5 ) Γ ( 4 7 ) 6 x 3 c o s ( 5 ) Γ ( 4 1 ) Γ ( 4 3 ) 2 F 3 ( 4 1 , 4 3 2 1 , 4 5 , 4 7 − 4 9 x 4 )
Ahora simplificar:
2 x 5 sin ( 5 ) 2 F 3 ( 3 4 , 5 4 3 2 , 7 4 , 9 4 | − 9 x 4 4 ) 5 − 2 x 3 cos ( 5 ) 2 F 3 ( 1 4 , 3 4 1 2 , 5 4 , 7 4 | − 9 x 4 4 ) 3 + 6 π x 2 cos ( 5 ) C ( 6 x π ) 6 − 6 π x 2 sin ( 5 ) S ( 6 x π ) 6 \frac{2 x^{5} \sin{\left(5 \right)} {{}_{2}F_{3}\left(\begin{matrix} \frac{3}{4}, \frac{5}{4} \\ \frac{3}{2}, \frac{7}{4}, \frac{9}{4} \end{matrix}\middle| {- \frac{9 x^{4}}{4}} \right)}}{5} - \frac{2 x^{3} \cos{\left(5 \right)} {{}_{2}F_{3}\left(\begin{matrix} \frac{1}{4}, \frac{3}{4} \\ \frac{1}{2}, \frac{5}{4}, \frac{7}{4} \end{matrix}\middle| {- \frac{9 x^{4}}{4}} \right)}}{3} + \frac{\sqrt{6} \sqrt{\pi} x^{2} \cos{\left(5 \right)} C\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right)}{6} - \frac{\sqrt{6} \sqrt{\pi} x^{2} \sin{\left(5 \right)} S\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right)}{6} 5 2 x 5 s i n ( 5 ) 2 F 3 ( 4 3 , 4 5 2 3 , 4 7 , 4 9 − 4 9 x 4 ) − 3 2 x 3 c o s ( 5 ) 2 F 3 ( 4 1 , 4 3 2 1 , 4 5 , 4 7 − 4 9 x 4 ) + 6 6 π x 2 c o s ( 5 ) C ( π 6 x ) − 6 6 π x 2 s i n ( 5 ) S ( π 6 x )
Añadimos la constante de integración:
2 x 5 sin ( 5 ) 2 F 3 ( 3 4 , 5 4 3 2 , 7 4 , 9 4 | − 9 x 4 4 ) 5 − 2 x 3 cos ( 5 ) 2 F 3 ( 1 4 , 3 4 1 2 , 5 4 , 7 4 | − 9 x 4 4 ) 3 + 6 π x 2 cos ( 5 ) C ( 6 x π ) 6 − 6 π x 2 sin ( 5 ) S ( 6 x π ) 6 + c o n s t a n t \frac{2 x^{5} \sin{\left(5 \right)} {{}_{2}F_{3}\left(\begin{matrix} \frac{3}{4}, \frac{5}{4} \\ \frac{3}{2}, \frac{7}{4}, \frac{9}{4} \end{matrix}\middle| {- \frac{9 x^{4}}{4}} \right)}}{5} - \frac{2 x^{3} \cos{\left(5 \right)} {{}_{2}F_{3}\left(\begin{matrix} \frac{1}{4}, \frac{3}{4} \\ \frac{1}{2}, \frac{5}{4}, \frac{7}{4} \end{matrix}\middle| {- \frac{9 x^{4}}{4}} \right)}}{3} + \frac{\sqrt{6} \sqrt{\pi} x^{2} \cos{\left(5 \right)} C\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right)}{6} - \frac{\sqrt{6} \sqrt{\pi} x^{2} \sin{\left(5 \right)} S\left(\frac{\sqrt{6} x}{\sqrt{\pi}}\right)}{6}+ \mathrm{constant} 5 2 x 5 s i n ( 5 ) 2 F 3 ( 4 3 , 4 5 2 3 , 4 7 , 4 9 − 4 9 x 4 ) − 3 2 x 3 c o s ( 5 ) 2 F 3 ( 4 1 , 4 3 2 1 , 4 5 , 4 7 − 4 9 x 4 ) + 6 6 π x 2 c o s ( 5 ) C ( π 6 x ) − 6 6 π x 2 s i n ( 5 ) S ( π 6 x ) + constant