Sr Examen
Integral de 7x^2*sin(ax) dx
Solución
Ha introducido
[src]
1 / | | 2 | 7*x *sin(a*x) dx | / 0
$$\int\limits_{0}^{1} 7 x^{2} \sin{\left(a x \right)}\, dx$$
Integral((7*x^2)*sin(a*x), (x, 0, 1))
Respuesta (Indefinida)
[src]
// 0 for a = 0\
|| |
|| //cos(a*x) x*sin(a*x) \ |
/ || ||-------- + ---------- for a != 0| |
| || || 2 a | | // 0 for a = 0\
| 2 || || a | | 2 || |
| 7*x *sin(a*x) dx = C - 14*|<-|< | | + 7*x *|<-cos(a*x) |
| || || 2 | | ||---------- otherwise|
/ || || x | | \\ a /
|| || -- otherwise | |
|| \\ 2 / |
||-------------------------------------- otherwise|
\\ a /
$$\int 7 x^{2} \sin{\left(a x \right)}\, dx = C + 7 x^{2} \left(\begin{cases} 0 & \text{for}\: a = 0 \\- \frac{\cos{\left(a x \right)}}{a} & \text{otherwise} \end{cases}\right) - 14 \left(\begin{cases} 0 & \text{for}\: a = 0 \\- \frac{\begin{cases} \frac{x \sin{\left(a x \right)}}{a} + \frac{\cos{\left(a x \right)}}{a^{2}} & \text{for}\: a \neq 0 \\\frac{x^{2}}{2} & \text{otherwise} \end{cases}}{a} & \text{otherwise} \end{cases}\right)$$
Respuesta
[src]
/ 14 7*cos(a) 14*cos(a) 14*sin(a) |- -- - -------- + --------- + --------- for And(a > -oo, a < oo, a != 0) | 3 a 3 2 < a a a | | 0 otherwise \
$$\begin{cases} - \frac{7 \cos{\left(a \right)}}{a} + \frac{14 \sin{\left(a \right)}}{a^{2}} + \frac{14 \cos{\left(a \right)}}{a^{3}} - \frac{14}{a^{3}} & \text{for}\: a > -\infty \wedge a < \infty \wedge a \neq 0 \\0 & \text{otherwise} \end{cases}$$
=
=
/ 14 7*cos(a) 14*cos(a) 14*sin(a) |- -- - -------- + --------- + --------- for And(a > -oo, a < oo, a != 0) | 3 a 3 2 < a a a | | 0 otherwise \
$$\begin{cases} - \frac{7 \cos{\left(a \right)}}{a} + \frac{14 \sin{\left(a \right)}}{a^{2}} + \frac{14 \cos{\left(a \right)}}{a^{3}} - \frac{14}{a^{3}} & \text{for}\: a > -\infty \wedge a < \infty \wedge a \neq 0 \\0 & \text{otherwise} \end{cases}$$
Piecewise((-14/a^3 - 7*cos(a)/a + 14*cos(a)/a^3 + 14*sin(a)/a^2, (a > -oo)∧(a < oo)∧(Ne(a, 0))), (0, True))
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.