Tomamos como el límite
$$\lim_{x \to 1^+}\left(\frac{5 x^{2} + \left(14 - 9 x\right)}{x^{2} + 4}\right)$$
cambiamos
$$\lim_{x \to 1^+}\left(\frac{5 x^{2} + \left(14 - 9 x\right)}{x^{2} + 4}\right)$$
=
$$\lim_{x \to 1^+}\left(\frac{5 x^{2} - 9 x + 14}{x^{2} + 4}\right)$$
=
$$\lim_{x \to 1^+}\left(\frac{5 x^{2} - 9 x + 14}{x^{2} + 4}\right) = $$
$$\frac{-9 + 5 \cdot 1^{2} + 14}{1^{2} + 4} = $$
= 2
Entonces la respuesta definitiva es:
$$\lim_{x \to 1^+}\left(\frac{5 x^{2} + \left(14 - 9 x\right)}{x^{2} + 4}\right) = 2$$