Tomamos como el límite
$$\lim_{x \to 2^+}\left(\frac{- 7 x + \left(x^{2} + 10\right)}{8 - x^{2}}\right)$$
cambiamos
$$\lim_{x \to 2^+}\left(\frac{- 7 x + \left(x^{2} + 10\right)}{8 - x^{2}}\right)$$
=
$$\lim_{x \to 2^+}\left(\frac{\left(x - 5\right) \left(x - 2\right)}{8 - x^{2}}\right)$$
=
$$\lim_{x \to 2^+}\left(- \frac{\left(x - 5\right) \left(x - 2\right)}{x^{2} - 8}\right) = $$
$$- \frac{\left(-5 + 2\right) \left(-2 + 2\right)}{-8 + 2^{2}} = $$
= 0
Entonces la respuesta definitiva es:
$$\lim_{x \to 2^+}\left(\frac{- 7 x + \left(x^{2} + 10\right)}{8 - x^{2}}\right) = 0$$