Tomamos como el límite
$$\lim_{x \to 0^+}\left(\frac{\left(x - 2\right) \left(x + 1\right)^{2}}{\left(1 - x\right)^{2}}\right)$$
cambiamos
$$\lim_{x \to 0^+}\left(\frac{\left(x - 2\right) \left(x + 1\right)^{2}}{\left(1 - x\right)^{2}}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\left(x - 2\right) \left(x + 1\right)^{2}}{\left(x - 1\right)^{2}}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\left(x - 2\right) \left(x + 1\right)^{2}}{\left(x - 1\right)^{2}}\right) = $$
2
1 *(-2)
------- =
2
(-1)
= -2
Entonces la respuesta definitiva es:
$$\lim_{x \to 0^+}\left(\frac{\left(x - 2\right) \left(x + 1\right)^{2}}{\left(1 - x\right)^{2}}\right) = -2$$