Tomamos como el límite
$$\lim_{x \to 2^+}\left(\frac{- 10 x + \left(x^{2} + 25\right)}{x^{2} - 5}\right)$$
cambiamos
$$\lim_{x \to 2^+}\left(\frac{- 10 x + \left(x^{2} + 25\right)}{x^{2} - 5}\right)$$
=
$$\lim_{x \to 2^+}\left(\frac{\left(x - 5\right)^{2}}{x^{2} - 5}\right)$$
=
$$\lim_{x \to 2^+}\left(\frac{\left(x - 5\right)^{2}}{x^{2} - 5}\right) = $$
$$\frac{\left(-5 + 2\right)^{2}}{-5 + 2^{2}} = $$
= -9
Entonces la respuesta definitiva es:
$$\lim_{x \to 2^+}\left(\frac{- 10 x + \left(x^{2} + 25\right)}{x^{2} - 5}\right) = -9$$