Tomamos como el límite
$$\lim_{x \to -1^+}\left(\frac{7 x^{3} + \left(x + 1\right)}{x^{3} + 2}\right)$$
cambiamos
$$\lim_{x \to -1^+}\left(\frac{7 x^{3} + \left(x + 1\right)}{x^{3} + 2}\right)$$
=
$$\lim_{x \to -1^+}\left(\frac{7 x^{3} + x + 1}{x^{3} + 2}\right)$$
=
$$\lim_{x \to -1^+}\left(\frac{7 x^{3} + x + 1}{x^{3} + 2}\right) = $$
$$\frac{7 \left(-1\right)^{3} - 1 + 1}{\left(-1\right)^{3} + 2} = $$
= -7
Entonces la respuesta definitiva es:
$$\lim_{x \to -1^+}\left(\frac{7 x^{3} + \left(x + 1\right)}{x^{3} + 2}\right) = -7$$