Tomamos como el límite
$$\lim_{x \to 1^+}\left(\frac{x^{2} - 2}{5 x + \left(2 x^{2} - 7\right)}\right)$$
cambiamos
$$\lim_{x \to 1^+}\left(\frac{x^{2} - 2}{5 x + \left(2 x^{2} - 7\right)}\right)$$
=
$$\lim_{x \to 1^+}\left(\frac{x^{2} - 2}{\left(x - 1\right) \left(2 x + 7\right)}\right)$$
=
$$\lim_{x \to 1^+}\left(\frac{x^{2} - 2}{\left(x - 1\right) \left(2 x + 7\right)}\right) = $$
False
= -oo
Entonces la respuesta definitiva es:
$$\lim_{x \to 1^+}\left(\frac{x^{2} - 2}{5 x + \left(2 x^{2} - 7\right)}\right) = -\infty$$