Tomamos como el límite
$$\lim_{x \to 0^+}\left(\frac{- x^{3} + x^{2}}{5 x^{2}}\right)$$
cambiamos
$$\lim_{x \to 0^+}\left(\frac{- x^{3} + x^{2}}{5 x^{2}}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\left(-1\right) x^{2} \left(x - 1\right)}{5 x^{2}}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{1}{5} - \frac{x}{5}\right) = $$
$$\frac{1}{5} - 0 = $$
= 1/5
Entonces la respuesta definitiva es:
$$\lim_{x \to 0^+}\left(\frac{- x^{3} + x^{2}}{5 x^{2}}\right) = \frac{1}{5}$$