Expresión ((-x)vy)((-y)vx)(-xz)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
z∧¬x∧(x∨¬y)∧(y∨¬x)=z∧¬x∧¬y
z∧¬x∧¬y
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 0 |
+---+---+---+--------+
Ya está reducido a FNC
z∧¬x∧¬y
Ya está reducido a FND
z∧¬x∧¬y
z∧¬x∧¬y
z∧¬x∧¬y