Sr Examen
Expresión ac->a∨¬(ca)
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Solución
Ha introducido
[src]
(a∧c)⇒(a∨(¬(a∧c)))
$$\left(a \wedge c\right) \Rightarrow \left(a \vee \neg \left(a \wedge c\right)\right)$$
Solución detallada
$$\neg \left(a \wedge c\right) = \neg a \vee \neg c$$
$$a \vee \neg \left(a \wedge c\right) = 1$$
$$\left(a \wedge c\right) \Rightarrow \left(a \vee \neg \left(a \wedge c\right)\right) = 1$$
$$a \vee \neg \left(a \wedge c\right) = 1$$
$$\left(a \wedge c\right) \Rightarrow \left(a \vee \neg \left(a \wedge c\right)\right) = 1$$
Tabla de verdad
+---+---+--------+ | a | c | result | +===+===+========+ | 0 | 0 | 1 | +---+---+--------+ | 0 | 1 | 1 | +---+---+--------+ | 1 | 0 | 1 | +---+---+--------+ | 1 | 1 | 1 | +---+---+--------+